How do you solve log_3 42-log_3n=log_3 7?
1 Answer
Apr 30, 2018
Explanation:
We should use
log_a n - log_a m = log_a(n/m) .
Therefore:
log_3(42/n) = log_3 7
42/n = 7
7n =42
n = 6
Hopefully this helps!
