How do you solve $log (3x+5)-log (x-5)=log 8$ ?

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Answer 1 · 2016-04-09T07:25:03

$=>log((3x+5)/(x-5))=log8$
$=>((3x+5)/(x-5))=8$
$=>(3x+5)=8(x-5)$
$=>8x-40-3x-5=0$
$=>5x=45$
$:. x =9$

How do you solve log (3x+5)-log (x-5)=log 8log (3x+5)-log (x-5)=log 8?