How do you solve $log_4(1-x)=1$ ?

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Answer 1 · 2015-07-22T21:40:34

I found: $x=-3$

Use the definition of log as:
$log_ax=b ->x=a^b$
to get:
$1-x=4^1$
$x=1-4$
$x=-3$

How do you solve log_4(1-x)=1log_4(1-x)=1?