How do you solve $log_4 3 + 5 log_4 x = log_4 7$ ?

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Answer 1 · 2018-03-29T12:54:52

Solution: $x ~~1.185(3dp)$

$log_4 3 +5 log_4 x=log_4 7$ or

$log_4 3 + log_4 x^5=log_4 7$ or

$log_4 (3*x^5)=log_4 7$ or

$3x^5=7 or x^5 =7/3 or x = root(5)(7/3)~~1.185(3dp)$

Solution: $x ~~1.185(3dp)$ [Ans]

How do you solve log_4 3 + 5 log_4 x = log_4 7log_4 3 + 5 log_4 x = log_4 7?