Question

How do you solve `log_4x=3`?

Answer 1

x = 64

Explanation:

`color(orange)"Reminder"`

`color(red)(|bar(ul(color(white)(a/a)color(black)(log_b x=ahArrx=b^a)color(white)(a/a)|)))`

here a = 3 and b = 4

`rArrlog_4 x=3rArrx=4^3=64`