Question

How do you solve `log_6 (x + 2) = log_6 (3x)`?

Answer 1

`x=1`

Explanation:

`color(blue)(log_x(y)=log_x(z)=>y=z, if y>0 and z>0`

`log_6(x+2)=log_6(3x)`

`x+2=3x and x+2>0 and 3x>0`

`2x=2 and x> -2 and x>0`

`x=1 and x>0`

`x=1`