Question

How do you solve `log_7 7(x+1) + log_7 (x-5)=1`?

Answer 1

`x = 2 ± 2sqrt 2`

Explanation:

`log a + log b = log (ab)`, then
`log_7 [7(x+1)(x-5)] = 1`

`log_b a = c \Rightarrow b^c = a`, then
`7^1 = 7(x+1)(x-5)`

`1 = (x+1)(x-5)`, continue with Baskara