How do you solve ${log}_{a} X = 3 {log}_{a} 2$ $Log_a X = 3 Log_a 2$ ?

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Answer 1 · 2018-06-22T17:51:18

x=8

just apply $a \cdot log (b) = log (b^{a})$ $a*log(b)=log(b^a)$
then cancel the $log$ $log$ s and you get $x = 2^{3}$ $x=2^3$ or $x = 8$ $x=8$

How do you solve Log_a X = 3 Log_a 2 logaX=3loga2Log_a X = 3 Log_a 2 ?