How do you solve $log_d 12 = 6$ ?

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Answer 1 · 2015-12-17T03:55:06

$(12)^(1/6)=d$

To undo a logarithm, raise both sides to the power of the base of the logarithm.

$log_d12=6$

$d^(log_d12)=d^6$

$12=d^6$

$(12)^(1/6)=(d^6)^(1/6)$

$(12)^(1/6)=d$

How do you solve log_d 12 = 6log_d 12 = 6?