Question

How do you solve `log x = 1.8`?

Answer 1

`x= 10^(1.8) ~~63.096`

Explanation:

`log x` means `log_10 x`

By definition
`color(white)("XXX")log_b p = q`
is equivalent to
`color(white)("XXX")p=b^q`

Therefore
`color(white)("XXX")log_10 x = 1.8`
is equivalent to
`color(white)("XXX")x= 10^(1.8)`
(which can be evaluated using a calculator as approximately `63.096`)