How do you solve $log _(x+2) 1000 = 3$ ?

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Answer 1 · 2016-05-08T16:23:41

$x =8$ .

Use inversion $a =b^c$ for $c=log_b a$ .

Here, $1000=(x+2)^3$

So, $x+2=1000 ^(1/3)=(10^3)^(1/3)=10^((1/3)(3))=10^1=10$

x=8..

How do you solve log _(x+2) 1000 = 3log _(x+2) 1000 = 3?