How do you solve $log x^2 =2$ ?

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Answer 1 · 2015-10-05T00:10:20

$x = +-10$

Assuming that's the common log, take the base 10 exponential of both sides, that is, the "sideth" power of 10.

$log(x^2) = 2$
$x^2 = 10^2$

Take the root

$x = +-10$

Since $x^2$ is positive for all values of $x$ the only value of $x$ we can't have is $0$ , so both answers are okay.

How do you solve log x^2 =2log x^2 =2?