How do you solve $log (x) - 2 = log (x - 4)$ $Log(x)-2=log(x-4)$ ?

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Answer 1 · 2018-03-28T16:44:31

x=4/99

$log (x) - 2 = log (x - 4)$ $log(x)-2=log(x-4)$

$\frac{x}{10^{2}} = x - 4, \Leftrightarrow x > 0 and x > 4$ $x/10^2=x-4,iff x>0 and x>4$

$\frac{x}{10^{2}} - x = - 4$ $x/10^2-x=-4$

$x - 100 x = - 400$ $x-100x=-400$

$- 99 x = - 400$ $-99x=-400$

$x = \frac{400}{99}$ $x=400/99$

x>4 so the solution is correct.

How do you solve Log(x)-2=log(x-4)log(x)−2=log(x−4)Log(x)-2=log(x-4)?