How do you solve log (x+3)=1-logx?

1 Answer
P dilip_k
Mar 11, 2016

=>x=-5 and x=2

Explanation:

log(x+3)+logx =1
=>log((x+3)xxx) =log10
=>x^2+3x=10
=>x^2+3x-10=0
=>x^2+5x-2x-10=0
=>x(x+5)-2(x+5)=0
=>(x+5)(x-2)=0
=>x=-5 and x=2

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