How do you solve $log_(x)44 = 2$ ?

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Answer 1 · 2015-11-13T18:11:15

$x=+-sqrt44$

By definition, $log_ax=yiffa^y=x$ .

So $thereforelog_x44=2iffx^2=44$ #

$iffx=+-sqrt44$

How do you solve log_(x)44 = 2log_(x)44 = 2?