Science

Math

Humanities

... and beyond

Socratic Meta
Featured Answers

Topics

How do you solve $log x + log 20 = 2$ $log x+log 20=2$ ?

1 Answer

Nov 29, 2015

$x = 5$ $x=5$

Explanation:

$log (x) + log (20) = log (20 x)$ $log(x)+log(20) = log(20x)$

So, if $log (x) + log (20) = 2$ $log(x)+log(20)=2$
then
$XXX log (20 x) = 2$ $color(white)("XXX")log(20x)=2$

$\Rightarrow XX 10^{log (20 x)} = 10^{2}$ $rArrcolor(white)("XX")10^(log(20x)) = 10^2$

$\Rightarrow XX 20 x = 100$ $rArrcolor(white)("XX")20x = 100$

$\Rightarrow XX x = 5$ $rArrcolor(white)("XX")x=5$

Related questions

See all questions in Logarithmic Models

Impact of this question

5391 views around the world

You can reuse this answer
Creative Commons License