How do you solve $log x - log(8-5x) = 2$ ?

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Answer 1 · 2018-05-24T01:52:44

$logx-log(8-5x)=2$

$=>log_10(x/(8-5x))=2$

$=>x/(8-5x)=100$

$=>x=(8-5x)*100$

$=>x=800-500x$

$=>501x=800$

$=>x=800/501$

How do you solve log x - log(8-5x) = 2log x - log(8-5x) = 2?