How do you solve log y = log (x-1) + 1logy=log(x−1)+1?

1 Answer
A. S. Adikesavan
Mar 25, 2016

y = 10 (x-1)10(x−1), x > 1.

Explanation:

Working on common logarithm, y = 10^((log(x-1)+1)y=10(log(x−1)+1).
10^(m+n)= 10^m 10^n10m+n=10m10n and 10^(log a)=a10loga=a.
y = (x-1) X 10^1=10(x-1)y=(x−1)X101=10(x−1)
Here, log(x-1)log(x−1) is defined for x > 1. So, the answer is suject yo x > 1..

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