How do you solve $log3(x+1) - log5(x-2)=2$ ?

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Answer 1 · 2016-05-06T17:36:45

$x=497/1003$

$log3(x+1)-log5(x-2)=2$

or $log(3(x+1))/(5(x-2))=log100$

or $(3(x+1))/(5(x-2))=100$

or $3x+3=100xx(5x-10)$

or $3x+3=500x-1000$

or $497x=1003$

or $x=497/1003$

How do you solve log3(x+1) - log5(x-2)=2log3(x+1) - log5(x-2)=2?