How do you solve $logx+log5=1$ ?

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Answer 1 · 2016-04-15T01:04:18

$x = 2$ (Assuming $Log$ is $Log_ 10$ )

$Log(x) + Log(5) = 1$

Applying $Log(a) + Log(b) = Log(ab)$
$-> Log(5x) = 1$
Assuming $Log$ is $Log_10$
$-> 5x = 10^1$
$5x = 10$
$x = 2$

How do you solve logx+log5=1logx+log5=1?