How do you solve $log x = log 5 + 3 log 3$ $logx = log5 + 3log3$ ?

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Answer 1 · 2016-04-21T17:47:29

$x = 135$ $x=135$

$log x = log 5 + {log 3}^{3}$ $log x= log 5 + log 3^3$

$log x = log 5 + log 27$ $log x = log5 + log 27$

$log x = log (5 \cdot 27)$ $log x=log (5*27)$

$log x = log 135$ $log x=log 135$

$x = 135$ $x=135$

How do you solve logx = log5 + 3log3logx=log5+3log3logx = log5 + 3log3?