How do you solve $n^ { 2} + 18n - 34= 0$ ?

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Answer 1 · 2017-03-10T20:10:41

The solutions are $S={-19.72, 1.72}$

We compare this equation to

$ax^2+bx+c=0$

$n^2+18n-34=0$

We calculate the discriminant

$Delta=b^2-4ac=18^2-4*1*(-34)$

$=324+136=460$

As $Delta>0$ , there are 2 real solutions

$n=(-b+-sqrt Delta)/(2a)$

$=(-18+-sqrt460)/2$

$n_1=(-18+21.448)/2=1.72$

$n_2=(-18-21.448)/2=-19.72$

How do you solve n^ { 2} + 18n - 34= 0n^ { 2} + 18n - 34= 0?