How do you solve (r+2)/7=5/7r+27=57?

1 Answer
Jim G.
May 2, 2018

r=3r=3

Explanation:

"since the fractions are equal and both have a denominator"since the fractions are equal and both have a denominator
"of 7 then the numerators will be equal"of 7 then the numerators will be equal

"solve "r+2=5solve r+2=5

"subtract 2 from both sides"subtract 2 from both sides

rArrr=5-2=3⇒r=5−2=3

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