How do you prove $sec x - cos x = sec x sin x$ $secx-cosx=secxsinx$ ?

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Answer 1 · 2016-07-21T00:28:08

$\frac{1}{cos x} - cos x \neq \frac{1}{cos x} \times sin x$ $1/cosx - cosx != 1/cosx xx sinx$

$\frac{1 - {cos}^{2} x}{cos x} \neq \frac{sin x}{cos x}$ $(1 - cos^2x)/cosx != sinx/cosx$

$\frac{{sin}^{2} x}{cos x} \neq \frac{sin x}{cos x}$ $sin^2x/cosx != sinx/cosx$

This identity is false!!

Hopefully this helps!

How do you prove secx-cosx=secxsinxsecx−cosx=secxsinxsecx-cosx=secxsinx?