How do you solve Sin^(2)[theta]=cos^(2)[theta]+1?

1 Answer
Hubert
Apr 25, 2016

theta=pi/2+kpi, k in mathbb(Z)

Explanation:

sin^2 theta=cos^2 theta +1
sin^2 theta=1-sin^2 theta +1
2sin^2 theta=2
sin^2 theta=1
sin theta=1 or sin theta=-1
theta=pi/2+2kpi or theta=(3pi)/2+2kpi
theta=pi/2+kpi, k in mathbb(Z)

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