How do you solve sin^2(x) - cos^2(x) = 1 + cos(x)sin2(x)−cos2(x)=1+cos(x)?

1 Answer
Vishwaksen Reddy V.
Oct 19, 2015

cosx=0cosx=0 or cosx = -1/2cosx=−12

Explanation:

sin^2 x - cos^2 x = 1 + cosxsin2x−cos2x=1+cosx
1-cos^2 x - cos^2 x = 1 + cosx1−cos2x−cos2x=1+cosx
-2cos^2 x - cosx = 0−2cos2x−cosx=0
cosx(2cosx+1)=0cosx(2cosx+1)=0
cosx=0cosx=0 or cosx = -1/2cosx=−12

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