How do you solve $sin (2 x) = sin ((\frac{x}{3}) - 2)$ $Sin(2x)=sin((x/3)-2)$ ?

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How do you solve $sin (2 x) = sin ((\frac{x}{3}) - 2)$ $Sin(2x)=sin((x/3)-2)$ ?

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Answer 1 · 2015-06-10T11:15:37

$x = - \frac{6}{5}$ $x=-6/5$

Explanation:

Given that
$sin (2 x) = sin (\frac{x}{3} - 2)$ $sin(2x)=sin(x/3-2)$
From equity,angles must be equal.
$cancel(sin)(2x)=cancel(sin)(x/3-2)$
$2x=x/3-2$
$=>6x=x-6$
$=>5x=-6$
$=>x=-6/5$

which is required solution.

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How do you solve $sin (2 x) = sin ((\frac{x}{3}) - 2)$ $Sin(2x)=sin((x/3)-2)$ ?

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Explanation:

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How do you solve $sin (2 x) = sin ((\frac{x}{3}) - 2)$ $Sin(2x)=sin((x/3)-2)$ ?