How do you solve $sin (3 x) = 1$ $sin(3x)=1$ ?

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Answer 1 · 2016-04-18T21:37:28

$S = {\frac{π}{6} + \frac{2 π}{3} n}$ $S={pi/6+(2pi)/3 n}$

$3 x = {sin}^{- 1} 1$ $3x=sin^-1 1$

$3 x = \frac{π}{2} + 2 π n$ $3x=pi/2+2pin$

$x = \frac{π}{2} \times \frac{1}{3} + 2 π n \times \frac{1}{3}$ $x=pi/2 xx 1/3+2pin xx 1/3$

$x = \frac{π}{6} + \frac{2 π}{3} n$ $x=pi/6+(2pi)/3 n$

$S = {\frac{π}{6} + \frac{2 π}{3} n}$ $S={pi/6+(2pi)/3 n}$

How do you solve sin(3x)=1 sin(3x)=1sin(3x)=1 ?