Question

How do you solve `(sin(x))^2 = 1/25`?

Answer 1

`11^@54; 168^@46; 191^@54; 348^@46`

Explanation:

`sin^2 x = 1/25` --> `sin x = +- 1/5`
Calculator and unit circle -->
a. `sin x = 1/5` --> There are 2 solution arcs:
`x = 11^@54` and `x = 180 - 11^@54 = 168^@46`
b. `sin x = - 1/5`. Two solution arcs:
`x = - 11.54` or `x = 360 - 11.54 = 348.46` (co-terminal arcs)
`x = 180 + 11.54 = 191.54`
Answers for `(0, 360^@)`:
`11^@54; 168^@46; 191^@54; 348^@46`