How do you solve $Sin x - tan x = 0$ in the interval [0, 2pi]?

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Answer 1 · 2016-02-16T02:17:24

$x=0^@, 180^@, 360^@$

from the given

$sin x - tan x=0$

$sin x - sin x/cos x=0$

factoring out sin x

$sin x(1-1/cos x)=0$

equate both factors to zero

$sin x=0$ and $1-1/cos x=0$

$x=sin^-1 0=0^@, 180^@$

also

$1-1/cos x=0$

$cos x-1=0$

$cos x=1$

$x=cos^-1 1=0^@, 360^@$

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How do you solve Sin x - tan x = 0Sin x - tan x = 0 in the interval [0, 2pi]?