Question

How do you solve `sin2 theta= sqrt 3/2`?

Answer 1

`S={30^@+180^@n, 60^@+180^@n}`

Explanation:

`2theta=sin^-1(sqrt3/2)`

`2theta=60^@+360^@n, 120^@+360^@n`

`theta=30^@+180^@n, 60^@+180^@n`

`S={30^@+180^@n, 60^@+180^@n}`