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How do you solve $sin2x=-1$ ?

2 Answers

Dec 9, 2016

$(3pi)/4 + kpi$

Explanation:

Use trig unit circle -->
sin 2x = - 1 -->
$2x = (3pi)/2 + 2kpi$
$x = (3pi)/4 + kpi$

Dec 9, 2016

$(3pi)/4 + kpi$

Explanation:

Use trig unit circle -->
sin 2x = - 1 -->
$2x = (3pi)/2 + 2kpi$
$x = (3pi)/4 + kpi$

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