How do you solve #sinx*cosx=1/2# for x in the interval [0,2pi)?
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1 Answer
Jan 31, 2016
Explanation:
Use trig identity: sin 2x = 2sin x.cos x
sin x.cos x =
sin 2x = 1 --> arc
Check
sin (pi/4).cos (pi)/4 = (sqrt2/2)(sqrt2/2) = 2/4 = 1/2 . OK
