How do you solve $sin x (sin x + 1) = 0$ $sinx(sinx+1)=0$ ?

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Answer 1 · 2015-04-15T12:49:55

$sin (x) (sin (x) + 1) = 0$ $sin(x)(sin(x)+1) = 0$
implies
either $sin (x) = 0$ $sin(x) = 0$
or $sin (x) = - 1$ $sin(x) = -1$

So
$x = \frac{π}{2} + n \cdot π$ $x= pi/2 +n*pi$ for all $n epsilon ZZ$

How do you solve sinx(sinx+1)=0sinx(sinx+1)=0sinx(sinx+1)=0?