How do you solve $sin x = \frac{\sqrt{3}}{2}$ $sinx=sqrt3/2$ ?

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Answer 1 · 2018-04-02T11:22:48

$x = 60$ $x = 60$

$sin 0 = \frac{\sqrt{0}}{2}$ $sin 0 =sqrt(0)/2$ , $sin 0 = 0$ $sin 0 = 0$

$sin 30 = \frac{\sqrt{1}}{2}$ $sin 30 =sqrt(1)/2$ , $sin 30 = \frac{1}{2}$ $sin 30 = 1/2$

$sin 45 = \frac{\sqrt{2}}{2}$ $sin 45 = sqrt(2)/2$

$sin 60 = \frac{\sqrt{3}}{2}$ $sin 60 =sqrt(3)/2$

$sin 90 = \frac{\sqrt{4}}{2}$ $sin 90 =sqrt(4)/2$ , $sin 90 = 1$ $sin 90 = 1$

For the exact cos values simply reverse the order of 0, 1, 2, 3 and 4 in the square root sign

How do you solve sinx=sqrt3/2sinx=√32sinx=sqrt3/2?