How do you solve $sqrt7^(6x)= 49^(x-6)$ ?

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Answer 1 · 2016-04-14T06:18:37

$x = -12$

Replace $sqrt7$ by $7^(1/2)$ and 49 by $7^2.$ .

Now, use $(a^m)^n=a^(mn)$ .

$7^(3x)=7^(2x-12)$ , Compare exponents..

$3x=2x-12$ .

$x=-12$ .

How do you solve sqrt7^(6x)= 49^(x-6)sqrt7^(6x)= 49^(x-6)?