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How do you solve $[tan 3 x] [tan (x - 1)] = 0$ $[tan 3x][tan (x-1)] = 0$ ?

1 Answer

May 31, 2016

for tan 3x=0, x= $n π$ $npi$ (general solution, where n is any integer)

for tan (x-1)=0, x= 1+ $n π$ $npi$ " "

Explanation:

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