Question

How do you solve `tan θ = sqrt 3`?

Answer 1

General solution is `npi+pi/3`, where`n` is an integer

Explanation:

`tantheta=sqrt3=tan(pi/3)`

i.e. `theta=pi/3`

A tangent function has a cycle of `pi` and repeats after every `pi`

Hence General solution is `npi+pi/3`, where`n` is an integer