How do you solve $tan (θ - (\frac{π}{2})) = 1$ $Tan(theta-(pi/2))=1$ ?

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How do you solve $tan (θ - (\frac{π}{2})) = 1$ $Tan(theta-(pi/2))=1$ ?

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Answer 1 · 2016-06-24T02:54:51

$t = \frac{π}{4} + k π$ $t = pi/4 + kpi$

Explanation:

Trig table and unit circle -->
tan (t - pi/2) = 1 = tan pi/4
(t - pi/2) = pi/4
t = pi/4 + pi/2 = 5pi/4
Answer: $t = \frac{π}{4} + k π$ $t = pi/4 + kpi$

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How do you solve $tan (θ - (\frac{π}{2})) = 1$ $Tan(theta-(pi/2))=1$ ?

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How do you solve Tan(theta-(pi/2))=1tan(θ−(π2))=1Tan(theta-(pi/2))=1?

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How do you solve $tan (θ - (\frac{π}{2})) = 1$ $Tan(theta-(pi/2))=1$ ?