Question

How do you solve `tan3x=1`?

Answer 1

`x=pi/12 + n pi/3, n in ZZ`

Explanation:

If `tan(w)=1` then `w=pi/4(+npi), n in ZZ`

Therefore if `tan(3x)=1` then `3x = pi/4(+npi), n in ZZ`

`rArr x= pi/12(+n (pi)/3), n in ZZ`