How do you solve $tantheta+cottheta=2$ in the interval $0 ≤ x ≤ 2pi$ ?

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Answer 1 · 2016-11-15T20:02:18

$theta = pi/4$

$sintheta/costheta + costheta/sintheta = 2$

$(sin^2theta + cos^2theta)/(costhetasintheta) = 2$

$sin^2theta + cos^2theta = 2costhetasintheta$

Recall the identities $sin^2beta + cos^2beta = 1$ and $2cosbetasinbeta = sin2beta$ .

$1 = sin2theta$

$pi/2 = 2theta$

$theta = pi/4$

Hopefully this helps!

How do you solve tantheta+cottheta=2tantheta+cottheta=2 in the interval 0 ≤ x ≤ 2pi0 ≤ x ≤ 2pi?