How do you solve the equation $log_4a+log_4 9=log_4 27$ ?

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Answer 1 · 2016-10-27T19:32:35

$a=3$

$log_4 a + log_4 9 = log_4 27$

$log_4 a + log_4 9 - log_4 27=0$

$log_4( (9a)/27)=0$ ----->Use properties $log_b x+log_b y = log_b (xy)$ and $log_b x-log_b y = log_b (x/y)$

$4^0=(9a)/27$

$1=(9a)/27$

$27=9a$

$a = 3$

How do you solve the equation log_4a+log_4 9=log_4 27log_4a+log_4 9=log_4 27?