How do you solve the following system?: $-1/2x+5y=-20 , -x+6y=7$

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Answer 1 · 2015-11-28T04:07:40

Answer: $(-155/2 , -47/2)$

Equation 1: $-1/2 x + 5y = -20$

Equation 2: $-x + 6y = 7$

Multiply equation 1 by $-2$ to eliminate fraction
$-2[-1/2x +5y =-20}] hArr$ $color(red)(x -10y = 40)$

Take equation 2, solve for $x$

$-x+6y = 7 hArr color(red)(6y-7=x)$

Substitute $color(red)(6y-7=x)$ into first equation

$color(red)(6y-7)-10y = 40$

$-4y= 47$

$color(blue)(y= -47/4)$

Substitute
$6(-47/4)-7= x$

$-141/2 -14/2 = x$

$color(blue)(-155/2 = x)$

How do you solve the following system?: -1/2x+5y=-20 , -x+6y=7 -1/2x+5y=-20 , -x+6y=7