How do you solve the following system?: $1/2x=y-1 , 1/3x=y-5$

Question

1409 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-07-25T17:06:40

$x=24$
$y=13$

$1/2x=y-1$ , $1/3x=y-5$
or
$x=2(y-1)$ , $x=3(y-5)$
or
$x=2y-2$ , $x=3y-15$
or
$2y-2=3y-15$
or
$3y-2y=15-2$
or
$y=13$ ---------Ans $1$

Since $x=2y-2$
or
$x=2(13)-2$
or
$x=26-2$
or
$x=24$ --------Ans $2$

How do you solve the following system?: 1/2x=y-1 , 1/3x=y-5 1/2x=y-1 , 1/3x=y-5