How do you solve the following system: $10y=42+2x , 3x - 3y = 2$ ?

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Answer 1 · 2016-08-31T11:23:08

$y=65/12 and x=73/12$

$x-y =2/3$

or $x=y + 2/3$

$10*y = 42 + 2*(y+(2/3))$

$10*y - 2*y = 42 + 4/3$

$8*y = (126 + 4)/3$

$8*y = 130/3$

$y = 130 /(8*3)$

$y = 65/12$

After this step, you can solve x:

$x = 65/12 + 2/3$

or $x= (65+8)/12$

$x= 73/12$

How do you solve the following system: 10y=42+2x , 3x - 3y = 2 10y=42+2x , 3x - 3y = 2 ?