How do you solve the following system?: $2 x + 3 y = - 5, y = 2 x + 9$ $2x+3y=-5 , y=2x+9$

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Answer 1 · 2018-05-06T23:45:14

$x = - 4, y = 1$ $x=-4, y=1$

Equation 2 already has $y$ $y$ as the subject of the equation, substitute that in place of the $y$ $y$ in the first equation.

$2 x + 3 (2 x + 9) = - 5$ $2x + 3(2x+9) = -5$

Simplify the equation and calculate the value of $x$ $x$ .

$2 x + 6 x + 27 = - 5$ $2x+6x+27 = -5$
$8 x = - 32$ $8x = -32$
$x = - 4$ $x=-4$

Then insert that value of $x$ $x$ into equation 2 to find the value of $y$ $y$ .

$y = 2 (- 4) + 9$ $y=2(-4)+9$
$y = - 8 + 9$ $y=-8+9$
$y = 1$ $y=1$

How do you solve the following system?: 2x+3y=-5 , y=2x+9 2x+3y=−5,y=2x+9 2x+3y=-5 , y=2x+9