How do you solve the following system: 2x-4y=6 , y + 4x = 16 ?

1 Answer
May 17, 2018

See a solution process below:

Explanation:

Step 1) Solve the second equation for y:

y + 4x = 16

y + 4x - color(red)(4x) = 16 - color(red)(4x)

y + 0 = 16 - 4x

y = 16 - 4x

Step 2) Substitute (16 - 4x) for y in the first equation and solve for x:

2x - 4y = 6 becomes:

2x - 4(16 - 4x) = 6

2x - (4 * 16) + (4 * 4x) = 6

2x - 64 + 16x = 6

2x + 16x - 64 = 6

(2 + 16)x - 64 + color(red)(64) = 6 + color(red)(64)

18x - 0 = 70

18x = 70

(18x)/color(red)(18) = 70/color(red)(18)

x = 35/9

Step 3) Substitute 35/9 for x in the solution to the second equation at the end of Step 1 and calculate y:

y = 16 - 4x becomes:

y = 16 - (4 xx 35/9)

y = 144/9 - 140/9

y = (144 - 140)/9

y = 4/9

The Solution Is:

x = 35/9 and y = 4/9

Or

(35/9, 4/9)