How do you solve the following system: $3x + y = 2 , 4x + y = 2$ ?

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Answer 1 · 2018-06-27T22:11:25

See a solution process below:

First, subtract the two equations:

$color(white)(-)4x + y = 2$
$-(3x + y = 2)$
$"---------------------"$

$color(white)(-)4x + y = 2$
$-3x - y = -2$
$"-----------------------"$
$1x + 0y = 0$

$1x = 0$

$x = 0$

Now, substitute $0$ for $x$ in either equation and calculate $y$ :

$3x + y = 2$ becomes:

$(3 xx 0) + y = 2$

$0 + y 2$

$y = 2$

The Solution Is:

$x = 0$ and $y = 2$

Or

$(0, 2)$

How do you solve the following system: 3x + y = 2 , 4x + y = 2 3x + y = 2 , 4x + y = 2 ?