How do you solve the following system: $3x+y=8, 2x-y=7$ ?

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Answer 1 · 2018-04-18T06:01:58

$x=3$
$y=-1$

Given -

$3x+y=8$ ------------- (1)
$2x-y=7$ ---------------(2) ----- $(1) + (2)$

$5x=15$

$x=15/5=3$

$x=3$

Substitute > $x=3$ in equation (1)

$3(3)+y=8$

$9+y=8$

$y=8-9=-1$

$y=-1$

How do you solve the following system: 3x+y=8, 2x-y=7 3x+y=8, 2x-y=7 ?