How do you solve the following system?: $4x-3y=15 , -6x+3y=17$

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Answer 1 · 2016-01-30T07:45:38

$(x,y)=(-16,-79/3)$

Solve by elimination

$4x-3y=15$

$-6x+3y=17$

If we loo carefully we can see that we can eliminate $3y$ in the second equation by $-3y$ in the first equation.

Add the equations

$rarr(4x-3y=15)+(-6x+3y=17)$

$rarr-2x=32$

$rarrx=32/-2=-16$

So,substitute the value of $x$ to the first equation:

$rarr4(-16)-3y=15$

$rarr-64-3y=15$

$rarr-3y=15+64$

$rarr-3y=79$

$rarry=-79/3$

So, $x=-16,y=-79/3$

How do you solve the following system?: 4x-3y=15 , -6x+3y=17 4x-3y=15 , -6x+3y=17